apoc.coll.runningTotal

使用示例

以下示例使用 APOC 和 Cypher 返回包含所有先前值的运行总计的列表

WITH [1,3,5,7,9] AS list
RETURN apoc.coll.runningTotal(list) AS output

使用 Cypher 的 reduce()

WITH [1,3,5,7,9] AS list
RETURN reduce(cumL = [head(list)], x IN tail(list) | cumL + (last(cumL) + x)) AS output

结果
输出
[1, 4, 9, 16, 25]