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apoc.agg.minItems

详情

语法

apoc.agg.minItems(item, value [, groupLimit ])

描述

返回一个 MAP {items: LIST<ANY>, value: ANY},其中 value 键是存在的最小值,items 表示所有具有相同值的项。项列表的大小可以限制为给定的最大大小。

参数

名称

类型

描述

item

ANY

要聚合的值。

value

ANY

选择最小值的来源值。

groupLimit

INTEGER

返回项数量的限制。默认值为:-1

返回

ANY

用法示例

本节示例基于以下人员及其出生日期的示例图

CREATE (:Person {name: "Tom Hanks", dateOfBirth: date("1956-07-09")});
CREATE (:Person {name: "Tom Cruise", dateOfBirth: date("1962-07-03")});
CREATE (:Person {name: "Nicole Kidman", dateOfBirth: date("1967-06-20")});
CREATE (:Person {name: "Matt Damon", dateOfBirth: date("1970-10-08")});
CREATE (:Person {name: "Carrie Fisher", dateOfBirth: date("1956-10-21")});
CREATE (:Person {name: "Bryan Cranston", dateOfBirth: date("1956-03-07")});

您可以通过运行以下查询来收集出生年份最小的人

MATCH (p:Person)
WITH apoc.agg.minItems(p, p.dateOfBirth.year) AS minItems
RETURN minItems.value AS value, minItems.items AS items;
结果
value items

1956

[(:Person {name: "Tom Hanks", dateOfBirth: 1956-07-09}), (:Person {name: "Carrie Fisher", dateOfBirth: 1956-10-21}), (:Person {name: "Bryan Cranston", dateOfBirth: 1956-03-07})]

您可以设置 groupLimit(第三个参数)来限制返回的项的数量

MATCH (p:Person)
WITH apoc.agg.minItems(p, p.dateOfBirth.year, 2) AS minItems
RETURN minItems.value AS value, minItems.items AS items;
结果
value items

1956

[(:Person {name: "Tom Hanks", dateOfBirth: 1956-07-09}), (:Person {name: "Carrie Fisher", dateOfBirth: 1956-10-21})]

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