apoc.path.combine
函数

详细信息
语法	`apoc.path.combine(path1, path2)`
描述	将两个给定的 `PATH` 值合并为一个 `PATH`。
参数	名称	类型	描述
	`path1`	`PATH`	要与第二个路径合并的第一个路径。
	`path2`	`PATH`	要与第一个路径合并的第二个路径。
返回	`PATH`

使用示例

本节中的示例基于以下示例图

MERGE (manUtd:Club {name: 'Man Utd'})
MERGE (juventus:Club {name: 'Juventus'})
MERGE (flamengo:Club {name: 'Flamengo'})

MERGE (premierLeague:League {name: 'Premier League'})
MERGE (serieA:League {name: 'Serie A'})
MERGE (brasileirao:League {name: 'Brasileirão'})

MERGE (england:Country {name: 'England'})
MERGE (brazil:Country {name: 'Brazil'})

MERGE (uefa:Confederation {name: 'UEFA'})

MERGE (manUtd)-[:IN_LEAGUE]->(premierLeague)
MERGE (premierLeague)-[:IN_COUNTRY]->(england)
MERGE (england)-[:IN_CONFEDERATION]->(uefa)

MERGE (juventus)-[:IN_LEAGUE]->(serieA)

MERGE (flamengo)-[:IN_LEAGUE]->(brasileirao)
MERGE (brasileirao)-[:IN_COUNTRY]->(brazil);

如果我们想从包含两个 OPTIONAL MATCH 子句的查询中创建一条路径，可以使用 apoc.path.combine 函数。

以下内容返回一条合并了 (club)-[:IN_LEAGUE]→(league) 和 (league)-[:IN_COUNTRY]→(country) 路径的路径

MATCH (club:Club)
OPTIONAL MATCH path1 = (club)-[:IN_LEAGUE]->(league)
OPTIONAL MATCH path2 = (league)-[:IN_COUNTRY]->(country)
RETURN club.name, apoc.path.combine(path1, path2) AS path
ORDER BY length(path);

结果
club.name	path
"Juventus"	(:Club {name: "Juventus"})-[:IN_LEAGUE]→(:League {name: "Serie A"})
"Man Utd"	(:Club {name: "Man Utd"})-[:IN_LEAGUE]→(:League {name: "Premier League"})-[:IN_COUNTRY]→(:Country {name: "England"})
"Flamengo"	(:Club {name: "Flamengo"})-[:IN_LEAGUE]→(:League {name: "Brasileirão"})-[:IN_COUNTRY]→(:Country {name: "Brazil"})

如果想要合并两个以上的 OPTIONAL MATCH 路径，请参阅 apoc.path.create。

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