apoc.coll.containsAll
函数在 Cypher 25 中已弃用

此函数已弃用。请改用 Cypher 的 all() 函数。

详细信息
语法	`apoc.coll.containsAll(coll1, coll2)`
描述	返回给定的值是否全部存在于指定的集合中。
参数	名称	类型	描述
	`coll1`	`LIST<ANY>`	要在其中搜索给定值的列表。
	`coll2`	`LIST<ANY>`	要检查是否存在于给定列表中的值列表。
返回	`布尔值 (BOOLEAN)`

使用示例

以下示例演示了如何分别使用 APOC 和 Cypher 检查一个集合是否包含另一个集合中的所有值

apoc.coll.containsAll

WITH [1,2,3,4,5] AS mainList, [3,7] AS sublist
RETURN apoc.coll.containsAll(mainList, sublist) AS output

Cypher 的 all()

WITH [1,2,3,4,5] AS mainList, [3,7] AS sublist
RETURN all(x IN sublist WHERE x IN mainList) AS output

结果
输出
false

apoc.coll.containsAll

WITH [1,2,3,4,5] AS mainList, [1,3] AS sublist
RETURN apoc.coll.containsAll(mainList, sublist) AS output

Cypher 的 all()

WITH [1,2,3,4,5] AS mainList, [1,3] AS sublist
RETURN all(x IN sublist WHERE x IN mainList) AS output

结果
输出
true

apoc.coll.containsAll

WITH [1,2,3,4,5] AS mainList, [4,1] AS sublist
RETURN apoc.coll.containsAll(mainList, sublist) AS output

Cypher 的 all()

WITH [1,2,3,4,5] AS mainList, [4,1] AS sublist
RETURN all(x IN sublist WHERE x IN mainList) AS output

结果
输出
true