match (n {name:“test”}) with [“a”,“b”,“c”] as attr_names, [1,2,3] as attr_values with [i in range(0, size(attr_names)-1) | n.attr_names[i] = n.attr_values[i]] return n

类似上面的cypher语句，但怎么也无法调试通，只能在list内循环。

感谢各位大侠们回答！